- 1 year ago
How can I open a file with it's default program via a package.json script
In a package.json
script, you can use a command-line tool to open a file with its default program. Here's an example using the start
command on Windows, macOS, and Linux:
json{
"scripts": {
"open-file": "start path/to/file.txt"
}
}
In this example, the open-file
script is defined. The command start path/to/file.txt
is used on Windows to open the file file.txt
with its default program. Replace path/to/file.txt
with the actual path of the file you want to open.
Note that the start
command is specific to Windows. On macOS, you can use the open
command, and on Linux, you can use the xdg-open
command. Here's an updated example that includes platform-specific commands:
json{
"scripts": {
"open-file": "start path/to/file.txt",
"open-file-macos": "open path/to/file.txt",
"open-file-linux": "xdg-open path/to/file.txt"
}
}
In this updated example, the open-file-macos
script uses the open
command to open the file on macOS, and the open-file-linux
script uses the xdg-open
command to open the file on Linux.
Choose the appropriate script based on the target platform and adjust the path/to/file.txt
accordingly.
To execute the script, you can use a package manager like npm or yarn. For example, run npm run open-file
or yarn open-file
in the command line to open the file with its default program as specified in the script.