- 1 year ago
how to delete images with a specific number with a bash script?
To delete images with a specific number using a bash script, you can use the rm
command with a wildcard pattern that matches the desired number. Here's an example script:
bash#!/bin/bash
number_to_delete="123" # Replace with the specific number you want to delete
# Navigate to the directory containing the images
cd /path/to/images/directory
# Delete images with the specific number
rm *"$number_to_delete"*.jpg # Replace .jpg with the appropriate image file extension
# Optional: Display a message with the number of deleted images
deleted_images=$(ls -l | grep "$number_to_delete" | wc -l)
echo "$deleted_images image(s) with the number $number_to_delete deleted."
Here's how the script works:
Set the
number_to_delete
variable to the specific number you want to delete.Change the directory to the location where the images are stored. Replace
/path/to/images/directory
with the actual path to your image directory.Use the
rm
command with a wildcard pattern to match and delete the images. In this example,*"$number_to_delete"*.jpg
matches any image file that contains the specified number in its filename and has the.jpg
extension. Adjust the pattern and file extension according to your image naming conventions.Optionally, you can display a message that indicates the number of deleted images. This is achieved by counting the number of lines that contain the specific number in the current directory's file listing.
Remember to make the script executable using chmod +x scriptname.sh
and replace scriptname.sh
with the desired filename for your script.
Use caution when running scripts that delete files, and make sure to test the script on a sample set of files before applying it to your actual image directory.