- 1 year ago
nested function overwrite my return buffer [duplicate]
This error usually occurs when a nested function tries to modify or overwrite a variable that is defined in the outer function, which is expected to be used by the outer function or returned to the caller. When the nested function modifies this variable, the outer function or the caller might not get the expected results.
To fix this issue, you can try one of the following solutions:
Avoid modifying the variable in the nested function: If the nested function only needs to read the variable, you can simply pass it as a parameter to the nested function, and avoid modifying it. This way, the outer function or the caller will get the expected results.
Use a different variable name in the nested function: If the nested function needs to modify the variable, you can declare a new variable with a different name inside the nested function and assign it the value of the outer variable. This way, the outer function or the caller will not be affected by the modifications in the nested function.
Use closures: You can also use closures to access the variable inside the nested function. This way, you can modify the variable inside the nested function, and the outer function or the caller will get the expected results. Here is an example:
pythondef outer_function():
var = "hello"
def nested_function():
nonlocal var
var += " world"
nested_function()
return var
result = outer_function()
print(result) # prints "hello world"
In this example, the nested_function
modifies the var
variable defined in the outer function using the nonlocal
keyword. The outer_function
returns the modified variable, which is "hello world".