python get origin information of windows files

To get the origin information of Windows files using Python, you can make use of the ctypes module to interact with the Windows API. Specifically, you can use the GetFileInformationByHandle function to retrieve the file information, including the file origin.

Here's an example code snippet that demonstrates how to get the origin information of a file in Python:

pythonCopy code
import os

import ctypes

from ctypes import wintypes



# Constants from the Windows API

INVALID_HANDLE_VALUE = wintypes.HANDLE(-1)

FILE_ATTRIBUTE_REPARSE_POINT = 0x400

FILE_FLAG_OPEN_REPARSE_POINT = 0x00200000

FILE_FLAG_BACKUP_SEMANTICS = 0x02000000

IO_REPARSE_TAG_SYMLINK = 0xA000000C



# Structure representing FILE_ATTRIBUTE_TAG_INFORMATION

class FILE_ATTRIBUTE_TAG_INFORMATION(ctypes.Structure):

    _fields_ = [("FileAttributes", wintypes.DWORD),

                ("ReparseTag", wintypes.DWORD)]



# Function to get the file origin information

def get_file_origin(file_path):

    # Open the file with appropriate flags and permissions

    handle = ctypes.windll.kernel32.CreateFileW(file_path, 0, 0, None, 

                                               FILE_FLAG_OPEN_REPARSE_POINT | FILE_FLAG_BACKUP_SEMANTICS, 

                                               0, None)



    if handle != INVALID_HANDLE_VALUE:

        # Get the file attributes and reparse tag information

        info = FILE_ATTRIBUTE_TAG_INFORMATION()

        result = ctypes.windll.kernel32.GetFileInformationByHandle(handle, ctypes.byref(info), ctypes.sizeof(info))



        # Close the file handle

        ctypes.windll.kernel32.CloseHandle(handle)



        if result != 0:

            # Check if the file is a symbolic link or junction point

            if info.FileAttributes & FILE_ATTRIBUTE_REPARSE_POINT and info.ReparseTag == IO_REPARSE_TAG_SYMLINK:

                return "Symbolic Link"

            else:

                return "Regular File"

        else:

            return "Unknown"

    else:

        return "Invalid Path"



# Example usage

file_path = r"C:\path\to\file.txt"

origin = get_file_origin(file_path)

print(f"File Origin: {origin}")

In this example, the get_file_origin function takes a file path as input and returns the origin information of the file. It checks if the file is a symbolic link or a regular file by examining the file attributes and reparse tag information.

Note that this code is specific to Windows and uses ctypes to call the Windows API functions.